Prove that three rimes the square of any side of an equilateral traingle is equal to four times the square of the altitude
Prove that three rimes the square of any side of an equilateral traingle is equal to four times the square of the altitude
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Answer:
this is your answer
Answer:3AB^2=4BC^2
Step-by-step explanation: let the sides of triangle be: a anthem the altitude perpendicular to the base divides it into to parts let it be a/2.
=AD=AC=a
BD=CD=a/2
BCis an altitude.
By Pythagoras theoram,
AB^2=BC^2+AC^2
(a^2) =(a/2^2) +BC^2
a^2=a^2/4+BC^2
a^2-a^2/4=BC^2
4a^2-a^2/4=BC^2
3a^2/4=BC^2
(as a is the one of sides of )
3AB^2=4BC^2