Q. 0.02 molar solution of acetic acid is 3 % ionised. Its ionisation constant is a) 0.9 ~ 10-3 b) 1.8 x 10 c) 18 x 10-5 d) 1.8 10-4
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Q. 0.02 molar solution of acetic acid is 3 % ionised. Its ionisation constant is a) 0.9 ~ 10-3 b) 1.8 x 10 c) 18 x 10-5 d) 1.8 10-4
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Answer:
2.1×10^-4
Explanation:
HCOOH+H2O → H3O + +COOH −
C O O
C−Cα Cα Cα
We know K a= C(1−α)C 2α 2
We are given C=0.2M
α=3.2%=0.032
Ka = (1−0.032)0.2×(0.032) 2
Ka =2.1×10 −4
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