Q 12 pls help. . .......
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Hence, if triangle ABC is similar to triangle PQR, we have:
AB/ PQ = BC/ QR = AC/ PR
Now, using a property of ratios, we have:
AB/ PQ = BC/ QR = AC/ PR = AB+BC+CA/ PQ+QR+PR
Hence, the ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides.
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