Q1=q , Q2 = -3q
F=-O.85N
r=28cm
q=?
According to Coloumb's law.
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Q1=q , Q2 = -3q
F=-O.85N
r=28cm
q=?
According to Coloumb's law.
...Don't spam...
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In this we have to find the value of q
According to Coloumbs law ,
F = K Q1Q2 / r^2
here,
K = 8.98 × 10^9
q1 and q2 = charges
r = distance between the charges
F = Force b/w the charges
Putting the values:
-0.85 = 8.98 × 10^9 (q) (-3q)/ (28)^2
-3q^2 = -0.85 × 28 × 28 / 8.98 × 10^9
q^2 = 666.4 × 10^-9 / 26.94
q^2 = 24.73 / 10^9
q = √24.73 / 10^9
q = 14.9 × 10^-9
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