Q.28.) If the circumference is 154m. What is its Area? *
A.) 1886.5 m²
B.) 1889.5 m²
C.) 1898.5 m²
D.) None of these
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Q.28.) If the circumference is 154m. What is its Area? *
A.) 1886.5 m²
B.) 1889.5 m²
C.) 1898.5 m²
D.) None of these
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1886.5m^2 is the right answer
Verified answer
Answer:
1886.5 m²
Explanation :
First we need to find the radius.
So,
Given,
Circumference = 154m.
2πr = 154.
[tex] \implies2 \times \frac{22}{7} \times r = 154[/tex]
[tex] \implies \: \frac{2 \times 22}{7} \times r = 154[/tex]
[tex] \implies \: r = 154 \times \frac{7}{2 \times 22} [/tex]
[tex] \implies 77 \times \frac{7}{22} [/tex]
[tex] \implies \: r \: = 7 \times \frac{7}{2} [/tex]
[tex] \implies \: r \: = 24.5m[/tex]
Now ,
Area of circle πr²
[tex] \implies \frac{22}{7} \times (24.5) {}^{2} [/tex]
[tex] \implies \frac{22}{7} \times ( \frac{49}{2} ) {}^{2} [/tex]
[tex] \implies \: \frac{22}{7} \times \frac{49}{2} \times \frac{49}{2} [/tex]
[tex] \implies \frac{11}{7} \times 49 \times \frac{49}{2} [/tex]
[tex] \implies \: 11 \times 7 \times \frac{49}{2} [/tex]
[tex] \implies11 \times \frac{343}{2} [/tex]
[tex] \implies \frac{3773}{2} [/tex]
[tex] \implies1886.5m {}^{2} [/tex]
Therefore ,radius of circular sheet is 24.5m
&
Area of circular sheet is 1886.5m²