Q.3) Diameter of the circular garden is 42 m. There is a 3.5 m wide road around the garden. Find the area of the road.
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Q.3) Diameter of the circular garden is 42 m. There is a 3.5 m wide road around the garden. Find the area of the road.
Best answer will be mark as brilliant
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Answer:
Diameter of the circular garden is 42 m. …
[Given]
∴ Radius of the circular garden (r) = 42/2 = 21 m
Width of the road = 3.5 m …[Given]
Radius of the outer circle (R) = radius (r) + width of the road = 21 + 3.5 = 24.5 m
Area of the road = area of outer circle – area of circular garden
= πR2 – πr2 = π(R2 – r2) = (22/7) [(24.5)2 – (21)2] = (22/7) (24.5 + 21) (24.5 – 21) ...[∵ a2 - b2 = (a + b)(a - b)]
= (22/7) x 45.5 x 3.5 = 22 x 45.5 x 0.5 = 500.50 sq. m
∴ The area of the road is 500.50 sq. m
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Diameter of the circular garden is 42 m. ...
[Given]
.. Radius of the circular garden (r) = 42/2
= 21 m
Width of the road = 3.5 m ...[Given]
Radius of the outer circle (R) = radius (r) + width of the road = 21+ 3.5 = 24.5 m
Area of the road = area of outer circle - area of circular garden
=п R2 - п r2 = T(R2 r2) = (22/7) [(24.5)2
- (21)2] =(22/7) (24.5+21) (24.5 - 21) ...[
a2 b2 = (a + b)(a - b)]
= (22/7) x 45.5 x 3.5 = 22 x 45.5 x 0.5 : = 500.50 sq. m
The area of the road is 500.50 sq.m
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