Q35.Solve the following equations 3(2y-2)=-3
please answer fast
class 7
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Q35.Solve the following equations 3(2y-2)=-3
please answer fast
class 7
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Answer:
= 3 ( 2y- 2 ) = 3
= 6y - 6 =3
Add 6 to both sides of the equation:
= 6y-6=3
=6y - 6+6 =3+6
Simplify :
= 6y - 6+6 = 3+ 6
= 6y =3+6
= 6y= 9
[tex] = \frac{6y}{6 } = \frac{9}{6} [/tex] Divide the number:
[tex] = y = \frac{9}{6} [/tex]
ans:
[tex]y = \frac{3}{2} [/tex]