Q5. A positive number is 5 time another number. If 21 is added to both the numbers, then one of the new numbers become twice of other new numbers. Find the original numbers.
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Q5. A positive number is 5 time another number. If 21 is added to both the numbers, then one of the new numbers become twice of other new numbers. Find the original numbers.
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Answer:
Step-by-step explanation:
let the smaller number = x
bigger number = 5x. -----(we need this.)
if 21 is added to both; 5x+21 = 2×(x+21)
5x + 21 = 2x + 42
5x - 2x = 42 - 21
3x =. 21
x = 21/3= 7
So the positive number is = 5×7 = 35
answer is 35
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Answer:
The original number is 35,28
Step by step explanation:
→let the original number = x
→A positive number is 5 times another number. If 21 is added to both the numbers one of the new number becomes twice the other number=5x+21=2[x+21]
→5x+21=2[x+21]
→5x+21=2x+42
→5x-2x=42-21
→3x=21
→x=21/3=3
The original numbers are 5×7=35,7+21=28