express in p P/qform 1) 0.750
2) 0.54bar on 54
3) 125.3 bar on 3
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express in p P/qform 1) 0.750
2) 0.54bar on 54
3) 125.3 bar on 3
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1)0.750=75/100
2)0.54 bar:
0.54 bar=x
100x=54.54bar
Subtracting x from 100x,we get,
99x=54
x=54/99
x=18/33
x=6/11
0.54 bar=6/11
3)125.3 bar :
let x be 125.3bar
10x=1253.3bar
subtracting x from 10x, we get,
9x=1128
x=1128/9
x=376/3
125.3bar=376/3.
hope it helps.
#aditya
2)x=0.545454...... 1) equation
100x=54.545454......... 2)equation
subtracting equation 2)-1)
100x-x=54-0
99x=54
x=54/99
3)x=125.333333......... 1) equation
10x=1253.333333.............2) equation
subtracting equation 2)-1)
10x-x=1253-125
9x=1128
x=1128/9
hope this helped
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