In a right angled triangle PQR, right angled at R, PR/QR = √3, then angle PQR is
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In a right angled triangle PQR, right angled at R, PR/QR = √3, then angle PQR is
Don't think or guess, solve it.
If you don't know, don't you dare to spam. I will definitely report.
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Answer:
60 degrees
Step-by-step explanation:
It is given that [tex]PR/QR = \sqrt{3}[/tex],
We know that [tex]tan 60 = \sqrt{3}[/tex],
[tex]tan Q = PR/QR[/tex],
[tex]tan Q = \sqrt{3}[/tex],
∴ [tex]Q = 60[/tex]