Question 19. A stone is dropped down a deep well from rest. The well is 50 meter deep.
How long will it take to reach the bottom of the well?
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Question 19. A stone is dropped down a deep well from rest. The well is 50 meter deep.
How long will it take to reach the bottom of the well?
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Answer:
As per the question,
Initial velocity of the stone, Vi=0, Depth of well, h=50 m
assuming g=9.8 m/s^2
h=Vi *t +(1/2)gt^2=0*t +(1/2)*9.8*t^2
9.8*t^2 =2*50
t^2 =100/9.8
t=[tex]\sqrt{100/9.8}[/tex] =3.194==3.2 second
If we take g=10
Then
t=[tex]\sqrt{100/10}[/tex] =[tex]\sqrt{10}[/tex] second =3.162==3.2 seconds
Explanation: