QUESTION:-
A shopkeeper bought two items at ₹ 450 each. He sold one at loss of 10%. At what price should he sell the other so as to gain 20% on the whole transaction?
TOPIC : PROFIT OR LOSS
SUBJECT: MATHS
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QUESTION:-
A shopkeeper bought two items at ₹ 450 each. He sold one at loss of 10%. At what price should he sell the other so as to gain 20% on the whole transaction?
TOPIC : PROFIT OR LOSS
SUBJECT: MATHS
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Answer:
Loss of 10%
[tex]450 \times \frac{10}{100} \\ 45[/tex]
so he sold it at 450 - 45 = 405
So he should sold it by
450 + 450 × 20 / 100
[tex]900 \times \frac{20}{10 0} \\ 180 \: \: rs[/tex]
So he should sold it at
900 + 180 = 1080 rs
1080 rs - 405
= 675 rs
hope this helps you out
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Verified answer
Given:
A shopkeeper bought two items at 450 each
He sold one item at 10% loss
To find:
At what price should he sell the other as to gain 20% on the whole transaction?
Solution:
Let "x" represents the selling price of the other item.
The total cost price of the two items = Rs. 450 × 2 = Rs. 900
We will use the following formula:
[tex] \begin{gathered}\boxed{\bold{S.P. = \frac{100 - L\%}{100}\times C.P. }}\\\\\boxed{\bold{S.P. = \frac{100 + G\%}{100}\times C.P. }}\end{gathered}[/tex]
Using the above formula, we get,
∴ The S.P. of the first item is,
=[tex] \dfrac{100 - 10}{100}[/tex]
= [tex] \dfrac{90}{100}\times 450[/tex]
= 0.9×450
= ₹405
and
∴ The total S.P. of the two items is,
=[tex] \dfrac{100 + 20}{100} \times 900[/tex]
= [tex] \dfrac{120}{100}\times 900[/tex]
= 1.2×900
= ₹1080
Now,
The S.P. of the other item should be,
= (Total S.P. of the two items) - (S.P. of the first item)
= (Rs. 1080) - (Rs. 405)
= Rs. 675