• Question from -- Pearson IIT Foundation book for class 6.
• Question for --
☆ Brainly Stars ☆
☆ Best users ☆
☆ Physics Newton ☆
Correct answer - 5 cm
Note:
*No spams allowed*
*Spams will be reported*
Share
• Question from -- Pearson IIT Foundation book for class 6.
• Question for --
☆ Brainly Stars ☆
☆ Best users ☆
☆ Physics Newton ☆
Correct answer - 5 cm
Note:
*No spams allowed*
*Spams will be reported*
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
⇝Given :
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⇝To Find :
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⇝Formula Used :
[tex]{\red{\bigstar \: \: {\orange{\underbrace{\underline{\overbrace{\overline{\mathfrak{Area = Side \times Side}}}}}}}}}[/tex]
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⇝Solution :
❒Here,
Area of leaf = Area of square = 25cm²
Side of square = ?
❒Than,
[tex]{\mapsto{\sf{Area = Side \times Side}}}[/tex]
[tex]{\leadsto{\sf{25cm² = Side \times Side}}}[/tex]
[tex]{\leadsto{\sf{25cm² = 2 \: {Side}}}}[/tex]
Side = √25
Side = 5m
❒So,
Side = 5m
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
Verified answer
Given:-
[tex] \sf \: Inside \: the \: outline \: of \: the \: leaf \: which is \: 25 {}^{2} [/tex]
To Find:-
[tex] \sf \: Length \: of \: Square \: [/tex]
[tex] \sf \: \red{Formula:-}[/tex]
[tex] \sf \: Area \: of \: square = Side {}^{2} [/tex]
[tex] \sf \red{Solution}[/tex]
[tex] \sf \: 25 = Side {}^{2} [/tex]
[tex] \sf \frak\pink{∴ side = 5 }[/tex]
Hence Answer is 5 Unit.