Question in attachment
for 8th class
chapter 1 and 2
please give answer fast
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Question in attachment
for 8th class
chapter 1 and 2
please give answer fast
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Answer:
Word Problems
Question.13: A positive number is 5 time another number. If 21 is added to both the numbers, then one of the new numbers become twice of other new numbers. Find the original numbers.
Solution: Let the smaller number be x
And another number = 5x
If 21 is added to both the numbers then as per the given condition;
5x+21 = 2×(x+21)
5x + 21 = 2x + 42
5x – 2x = 42 – 21
3x =. 21
x = 21/3= 7
Therefore, the positive number is = 5×7 = 35
Question.14: The sum of three consecutive multiples of 8 is 888. Find the multiple.
Solution: Let the multiples be x, x+8, x+16
Given, the sum of three consecutive multiples of 8 is 888
Thus,
x+x+8+x+16=888
3x+24=888
3x=888-24
3x =864
x =864/3
x =288
Therefore the multiples are:
x =288
x +8=296
x+16=304
Question.15: Five years ago, Anu was thrice as old as Sonu. After ten years, Anu will be twice as old as Sonu. How old are Anu and Sonu?
Solution:
Let us assume the present ages of Anu is x and Sonu is y.
According to the question:
x – 5 = 3(y – 5)
x – 5 = 3y – 15
x= 3y-15+5
x= 3y -10 ……………….. (1)
Again, as per question;
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x – 2y = 10
(3y – 10) – 2y = 10 (from equation 1)
3y-2y =10+10
y= 20
Substitute, y=20 in equation 1,
x = 3(20) -10
x =60 – 10
x = 50
Hence, the present ages of Anu is 50 years and of Sonu is 20 years.
Question 16: Three consecutive integers are as such they are taken in increasing order and multiplied by 2, 3, and 4, respectively, they add up to 56. Find these numbers.
Solution: Let us say the three consecutive numbers be x, x+1 and x+2.
Now as per the given question;
2×(x)+3×(x+1)+4×(x+2)=56
9x + 11 = 56
9x = 56-11
9x = 45
x = 45/9
x= 5
Therefore, the three consecutive numbers are 5, 6 and 7.
Question 17: The perimeter of a rectangular swimming pool is 154 meters. Its length is 2m more than twice its breadth. What are the length and the breadth of the pool?
Solution: Let the breadth of the pool =x
Length of the pool will be 2+2x.
Given, Perimeter of the pool = 154 m
We know, for a given rectangle,
Perimeter=2(length+breath)
By using this formula, we get;
154=2(2+2x+x)
77=2+3x
75=3x
x=25m
Hence, the breadth of the pool is 25m
and Length=2+2×25=52m
Question 18: Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Solution: Let first number be x
So, second number will be x+15
As per the given question;
x+x+15=95
x+x=95-15
2x=80
x=80/2
x=40
x=40
First number = 40
Second number = x+15=40+15=55
Hence, 40 + 55 = 95
Step-by-step explanation:
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