Question no.8 Class 10
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Verified answer
(i)
Given sin A = 1
= > sinA = sin 90
= > A = 90 ------ (1)
(ii)
Given : tan(A - B) = √3
= > tan(A - B) = tan 60
= > (A - B) = 60
= > 90 - B = 60 [from (i)]
= > -B = 60 - 90
= > -B = -30
= > B = 30.
Therefore, the value of A = 90 and B = 30.
Hope this helps!
tan(A-B) = tan 60°
A-B = 60° ------(i)
SinA = 1
SinA = Sin 90°
A = 90°
by putting value of a from equation second in equation 1
90-B = 60°
-B = 60°-90°
- B = -30°
B = 30°
A = 90°
hope it helps
thanks..
hope it helps
thank you..