Raju has certain notes of denominations 10 and 5 which amounts to 345. If the number of notes of each kind is interchanged, they amount to 45 less as before. Find the number of notes of each denominations
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Raju has certain notes of denominations 10 and 5 which amounts to 345. If the number of notes of each kind is interchanged, they amount to 45 less as before. Find the number of notes of each denominations
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Step-by-step explanation:
Let’s consider the number of 20 rupee notes to be x
And the number of 5 rupee notes be y
Then, according to the given conditions, we have
20x+5y=380 … (i) and
5x+20y=380−60
⇒5x+20y=320 … (ii)
Now, multiplying eq(i) by 4 and subtracting with eq(ii), we get
(80x+20y)−(5x+20y)=1520−320
⇒75x=1200
⇒x=751200
⇒x=16
On substituting the value of x in eq(i), we get
20(16)+5y=380
⇒320+5y=380
⇒5y=380−320=60
⇒y=560
⇒y=12
Therefore,
The number of 20 rupee notes =16 and
The number of 5 rupee notes =12
Answer:
solve the inequality for real
.