Resolve a vector R = 2i^-3 j^ into two perpendicular components such that one of its Commponents makes and angle of 45° with (+ x-axis)
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Resolve a vector R = 2i^-3 j^ into two perpendicular components such that one of its Commponents makes and angle of 45° with (+ x-axis)
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Answer
Explanation:
Answer:
The components are [tex]\sqrt{2}[/tex] and [tex]-\frac{3}{\sqrt{2} }[/tex].
Explanation:
We are given with vector [tex]R = 2i^-3 j^[/tex]
We need to resolve it in to two perpendicular components such that one of its components makes and angle of[tex]45[/tex] degrees with (+ [tex]x[/tex]-axis).
As per the given information,
The magnitude in positive [tex]x[/tex] axis is [tex]2[/tex] and in negative [tex]y[/tex] axis is [tex]3[/tex].
If it makes angle of [tex]45[/tex] degrees with [tex]x[/tex] axis,
[tex]r_{x} =2cos45=2*\frac{1}{\sqrt{2} } =\sqrt{2}[/tex]
and
[tex]r_{y} =-3sin45=-3*\frac{1}{\sqrt{2} } =-\frac{3}{\sqrt{2} }[/tex]
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