Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.
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Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.
Answer quality-
Neat and Clean
Don't Spam ❌
No Google
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Answer:
Let the force 10N makes an angle Φ with the inclined line
[tex]\fbox\red{Answer}[/tex]
Let the force 10N makes an angle θ with the inclined line
parallel component = 10×sinθ N ; perpendicular component = 10×cosθ N