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xy = a, xz = b, and yz = c
(xy)(xz) = ab
x^2 = ab/yz = ab/c
(xy)(yz) = ac
y^2 = ac/xz = ac/b
(xz)(yz) = bc
z^2 = bc/xy = bc/a
x^2 - y^2 + z^2 = ab/c - ac/b + bc/a <<< answer
Hope it helps u
Please mark as brainlist answer
Please mark as brainlist answer
Given xy = a ---- (1)
Given xz = b ---- (2)
Given yz = c ---- (3)
Multiply (1) & (2), we get
= > x^2yz = ab
= > x^2 = ab/yz
= >x^2 = ab/c ---- (4)
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Multiply (1) & (3), we get
= > xy^2z = ac
= > y^2 = ac/xz
= > y^2 = ac/b ---- (5)
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Multiply (2) & (3), we get
= > xyz^2 = bc
= > z^2 = bc/xy
= > z^2 = bc/a ---- (6)
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So,
From (4),(5),(6),
= > x^2 + y^2 + z^2
= > (ab/c) + (ac/b) + (bc/a).
Hope this helps!