road roller is cylindrical in shape. Its circular end has a diameter of 250 cm and its with 1 m 40 cm. Find the least number of revolutions that the roller must make in order to level playground that is 110 m * 25 m .
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road roller is cylindrical in shape. Its circular end has a diameter of 250 cm and its with 1 m 40 cm. Find the least number of revolutions that the roller must make in order to level playground that is 110 m * 25 m .
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Verified answer
Given:-
diameter of roller = 250 cm = 2.5m
width of roller = 1.4m
radius of the roller = 1.25m
We know that,
curved surface area = 2×22/7×1.25×1.40
= 44 × 1.25 × 0.20
=11m^2
area of ground = length × breath
= 25 × 10
= 250 m^2
number of revolutions to cover the field= Area of field/ CSA of roller.
= 250/11
= 22.727 revolutions approx.
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Answer:
diameter of roller = 250 cm = 2.5m
width of roller = 1.4m
radius of the roller = 1.25m
We know that,
curved surface area = 2×22/7×1.25×1.40
= 44 × 1.25 × 0.20
=11m^2
area of ground = length × breath
= 25 × 10
= 250 m^2
number of revolutions to cover the field= Area of field/ CSA of roller.
= 250/11
= 22.727 revolutions approx.
Step-by-step explanation:
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