rock is thrown vertically upward with a velocity of 24 metre per second how fast is it moving with when it reaches a height of 15 how long does it take to reach this height
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rock is thrown vertically upward with a velocity of 24 metre per second how fast is it moving with when it reaches a height of 15 how long does it take to reach this height
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Answer:
u=25ms−1
v=0ms−1
a=−9.8ms2
v=u+at
=>0=25+(−9.8)∗t
=>t=25/9.8
=>t=2.55sec
v2−u2=2ah
=>0−625=2∗(−9.8)∗h
Explanation:
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Answer:
v = 16.8m/s, t = 0.73s
Explanation:
Initial velocity, u = 24 m/s
height reached, s = 15m
velocity at that height, v = ?
we know that:
[tex]v^2 - u^2 = 2as\\ \\ \Rightarrow v^2 - 24^2 = 2 \times (-9.8) \times 15\\ \\ \Rightarrow v^2 = 24^2 - 2 \times 9.8 \times 15\\ \\ \Rightarrow v^2 = 576-294 = 282\\ \\ \Rightarrow v=\sqrt{282} = 16.8\ m/s[/tex]
So velocity at height 15m is 16.8 m/s.
to find time taken to reach this point,
v = u + at
⇒ 16.8 = 24 + (-9.8)t
⇒ 16.8 = 24 - 9.8t
⇒ 9.8t = 24 - 16.8 = 7.2
⇒ t = 7.2 / 9.8
⇒ t = 0.73s
Hence, it will take 0.73s to reach the height 15m