room is 15 metre long and 8th floor is to be covered with rectangular tiles each measuring 25 CM by 87 how many times with be required
room is 15 metre long and 8th floor is to be covered with rectangular tiles each measuring 25 CM by 87 how many times with be required
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Step-by-step explanation:
Answer
Open in answr app
We know, 50cm=0.5m and
25cm=0.25m
Tiles along the length of the room=0.515 = 30 tiles
Tiles along the length of the room=0.258 =32 tiles
Total number of tiles required =30×32 =960 tiles
To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.
Therefore,
(15−2)m(8−2)m
=(13×6)m
=78m2
Therefore, the room area is 15×8 = 120m2
The carpet area is 78m2
The fraction of the area uncovered =120120−78= 12042=207