(root a +root b ) (root c+ root )
use suitable indentity
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(root a +root b ) (root c+ root )
use suitable indentity
no spam!!
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Correction in the question:
[tex] \large\sf{ \underline{ \underline{\color{orange}{ (\sqrt{a} + \sqrt{b})( \sqrt{c} + \sqrt{d} ) }}}}[/tex]
[tex]\\[/tex]
Solution:
[tex] \sf \longrightarrow{( \sqrt{a} + \sqrt{b})( \sqrt{c} + \sqrt{d} ) }[/tex]
[tex] \sf {\longrightarrow \: \sqrt{a}( \sqrt{c} + \sqrt{d} ) + \sqrt{b} ( \sqrt{c} + \sqrt{d} }[/tex]
[tex] \sf{ \longrightarrow( \sqrt{a} \sqrt{c} + \sqrt{a} \sqrt{d}) + ( \sqrt{b} \sqrt{c} + \sqrt{b} \sqrt{d} )}[/tex]
[tex] \large\sf{\bold{ \longrightarrow} { \bold{ \color{pink}{\sqrt{ac} + \sqrt{ad} + \sqrt{bc} + \sqrt{bd}}}}}[/tex]
Pigga here
root a +root b ) (root c+ root )
In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal