5
A stone dropped from the top of tower travels 5 th of the height of tower during
the last second of fall. Height of the tower is : (take g = 10 m/s) :-
(1) 52 m
(2) 36 m
(3) 45 m
(4) 78 m
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5
A stone dropped from the top of tower travels 5 th of the height of tower during
the last second of fall. Height of the tower is : (take g = 10 m/s) :-
(1) 52 m
(2) 36 m
(3) 45 m
(4) 78 m
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Answer:
Trying to copy for exam
Verified answer
displacement of the first stone when second is dropped = 5m ,thus time
difference in dropping of the stones is t=
[tex] \frac{2h}{g} = 1 \\ h = \frac{1}{2} g {2}^{2} \\ =\frac{1}{2} (t - 1)^{2} + 25 \\ 2 = 3s \\ thus, \: h = 45m \\ [/tex]
45m is the correct answer....