A ball thrown up vertically returns to the thrower after 6 seconds. Find the velocity with which it was thrown up.
29 m/s
29.8 m/s
29.2 m/s
29.4 m/s
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A ball thrown up vertically returns to the thrower after 6 seconds. Find the velocity with which it was thrown up.
29 m/s
29.8 m/s
29.2 m/s
29.4 m/s
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Answer:
(a) Time of ascent is equal to the time of descent. The ball takes a total of 6 s for its upward and downward journey. Hence, it has taken 3 s to attain the maximum height. Hence, the ball was thrown upwards with a velocity of 29.4 m s−1
Explanation:
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Answer:
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Since,
Ball is thrown vertically then, we get
To find Initial velocity (u).
The ball returns to the ground after 6 seconds.
Thus the time taken by the ball to reach to the maximum height (h) is 3 seconds i.e t=3 s
Let the velocity with which it is thrown up be u
From Formula:
v=u+at
Putting all the values:
=>0m/s=u+(-10m/s²)×3 seconds
=>u=30m/s
Hence the velocity which it was thrown up was 30m/s
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