Find the velocity of a bullet of mass 10g which is fired from a pistol of
mass 1.5kg. The recoil velocity of the pistol is 2.5 m/s. Also pls tell that the recoil velocity will remain positive or we will change it to negative. The one coming with the most accurate answer and explanation will be marked as the brainliest. Pls help !!!!
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the velocity is णछतहज्ञ। ज्ञणमश्र तम। भतमभक्ष णतहज्ञ बम। घम। हज्ञ। ज्ञक्ष। ज्ञय। ज्ञरक्ष। मर क्षरज्ञक्ष। मंत्रालय चंद्र।
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Explanation:
Let the direction in which the bullet is fired be positive.
Therefore,
Mass of Bullet(m)=20 grams=0.02 kg
Mass of Pistol(M)=2 kg
Initial Velocity of Bullet(u)=0 m/s
Initial Velocity of Pistol(U)=0 m/s
Final Velocity of Bullet(v)=150 m/s
Final Velocity of Pistol(V)= Recoil Velocity of Bullet = ?
According to the Law of Conservation of Momentum,
mu + MU = mv + MV
(0.02)(0) + (2)(0) = (0.02)(150) + (2)(V)
0 + 0 = 3 + 2V
-3/2 = V
V = -1.5 m/s
Therefore, the recoil velocity of the pistol will be 1.5 m/s in the opposite direction.(As the sign is negative)
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