A bullet of mass 10g strikes a sand-bag at a speed of 10³m/s and gets embedded after travelling a distance of 5cm. Calculate:
i) The resistive force exerted by the sand on the bullet.
ii) The time taken by the bullet to come to rest.
Share
A bullet of mass 10g strikes a sand-bag at a speed of 10³m/s and gets embedded after travelling a distance of 5cm. Calculate:
i) The resistive force exerted by the sand on the bullet.
ii) The time taken by the bullet to come to rest.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Answer:
F=10^5,T=10^-4
Explanation:
Given A bullet of 10 g strike the sand bag at a speed of 1000 m/s and gets embedded after travelling 5 cm. calculate
(a)Resistive force exerted by sand on bullet.
(b)Time taken by bullet to come to rest.
Given mass of bullet m = 10 g = 0.01 kg
Speed v = 1000 m/s
Distance s = 5 cm = 0.05 m
We know that F = ma
and v^2 = u^2 – 2as
or a = v^2 – u^2 / 2s
Now F = m (v^2 – u^2 / 2s)
= 0.01 x (1000^2 – 0 / 2 x 0.05)
Resistive force will be F = 10^5 N
Now time taken to come to rest will be
S = (u + v / 2) t
So t = 2s / u + v
= 2 x 0.05 / 1000
t = 10 ^-4 secs
Please mark me as brainliest please