A body is thrown up with a velocity 50m/s . calculate the maximum height reached and the time taken to reach the maximum height
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A body is thrown up with a velocity 50m/s . calculate the maximum height reached and the time taken to reach the maximum height
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CORRECT QUESTION :
★ A body is thrown up with a velocity of 50 m/s. Calculate the maximum height reached and the time taken to reach the maximum height { g = 10 m/s². }
GIVEN :
• Initial velocity, u = 50 m/s.
final velocity, v = 0.
acceleration due to gravity, g = -10 m/s².
TO FIND :
• maximum height, s.
time taken, t.
45%
SOLUTION :
★ third equation of motion ★
v²-u² = 2gs.
u = Initial velocity.
• v = final velocity.
g= acceleration due to gravity.
s = maximum height.
(0)²-(50)² = 2(-10)s
» 0-2500 = -20 s
> -2500 = -20 s
s-2500/-20
s 2500/20
s 125 m.
★ first equation of motion ★
→ 050 + (-10) t
→ 050 - 10 t
→ 0-50-10 t
→-50-10 t
→ t= -50/-10
→ t = 50/10
t = 5 sec.
Hence the maximum height is 125 m and and time taken to reach the maximum height is 5 sec.