the ball is thrown vertically upwards with a velocity of 39 m/s calculate the maximum height to which it rises brainliest
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the ball is thrown vertically upwards with a velocity of 39 m/s calculate the maximum height to which it rises brainliest
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Answer :
Explanation :
Given :
[Acceleration due to gravity will be taken as negative, since in this case , the object is falling against the gravity]
[At the maximum hieght, final velocity of a object is 0 .i.e, v = 0]
To find :
Knowlwdge required :
Third equation of motion :
[Under gravity]
⠀⠀⠀⠀⠀⠀⠀⠀⠀v² = u² - 2gh
Where,
Solution :
By using the third equation of motion and substituting the values in it, we get :
⠀⠀=> v² = u² - 2gh
⠀⠀=> 0² = 39² - 2 × 10 × h
⠀⠀=> 0 = 39² - 20h
⠀⠀=> -39² = - 20h
⠀⠀=> 1521 = 20h
⠀⠀=> 1521/20 = h
⠀⠀=> 76.05 = h
⠀⠀⠀⠀⠀⠀⠀∴ h = 76.05 m
Therefore,