A constant force acts on an object of mass 5 kg for a duration of 2 seconds. It increases the object's velocity from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now if the force were applied for a duration of 5 s what would be the final velocity of the object????????
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Verified answer
Mass= 5 kgu = 3m/s
v = 7 m/s
t = 2s
acceleration = (v-u)/t = (7-3)/2 = 4/2 = 2m/s²
force = ma = 5×2 = 10N
now if the force had been applied for 5 seconds
final velocity = 3 + 2×5 = 13 m/s