2. an object travels 120 m with an initial velocity of 10 m/s for time 2 second ,find the acceleration and final velocity also.
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2. an object travels 120 m with an initial velocity of 10 m/s for time 2 second ,find the acceleration and final velocity also.
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Answer:
a=50cm/sec^2
v=110cm/sec
Explanation:
s=ut+1/2at^2
120=10(2)+1/2a4
120=20+2a
a=50cm/sec^2
v=u +at
=10+50(2)
v=110cm/sec
[tex] \rm \huge\blue{ \bold{Answer}}[/tex]
✒ Given:
✏ distance travelled by an object = 120m
✏ initial velocity = 10 m/s
✏ time interval = 2 s
✒ To Find:
✒ Formula:
✏ Kinematics equations are provided below...
[tex] \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \bold{ \rm{ \pink{d = ut + \frac{1}{2} a{t}^{2} }}}}} \: \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \bold{ \rm{ \red{v = u + at}}}}} \: [/tex]
✒ Calculation:
1) Acceleration
[tex] \implies \rm \: 120 =( 10 \times 2) + \frac{1}{2} a({2})^{2} \\ \\ \implies \rm \: 120 = 20 + 2a \\ \\ \implies \rm \: 100 = 2a \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \purple{a = 50 \: \frac{m}{ {s}^{2} } }}}}}[/tex]
2) Final velocity
[tex] \implies \rm \: v = 10 + (50 \times 2) \\ \\ \implies \rm \: v = 10 + 100 \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \green{v = 110 \: \frac{m}{s} }}}}}[/tex]