an object travelling with initial velocity 25 m/s goes on for 12 seconds before stopping ,find the acceleration and distance travelled
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an object travelling with initial velocity 25 m/s goes on for 12 seconds before stopping ,find the acceleration and distance travelled
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Explanation:
u= 25 m/s
v= 0 m/s
t= 12 s
by v = u + at,
0 = 25 + a(12)
a = -25/12 m/s^2
by s = ut + 1/2 at^2
s = 25(12) + 1/2(-25/12)(12)^2
s = 300 + 1/2(-25)(12)
s = 300 + ( - 150)
s = 300 - 150
s = 150 m
Hope you are satisfied.
Answer:
acceleration = -25/12 and distance=150m
Explanation:
intial velocity (u) =25m/s
final velocity (v) = 0m/s
time (t)=12s
acceleration =v-u /t
=0-25/12
=-25/12
distance = vt - 1/2 at²
= -1/2 × -25/12 × (12)²
=150m