a constant retarding force of 20n acts on a body of mass 10 kg moving initially with a speed of 10m/s how long does the body take to stop
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a constant retarding force of 20n acts on a body of mass 10 kg moving initially with a speed of 10m/s how long does the body take to stop
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Answer:
5s
Step-by-step explanation:
Given,
a=[tex]\frac{Force}{Mass}[/tex]
a = [tex]\frac{-20}{10}[/tex]
a = -2 m/s²
v = u + at
Final Velocity(v) = 0 m/s
Initial Velocity(u) = 10 m/s
Acceleration(a) = -2 m/s²
0 m/s = 10 m/s + (-2 m/s²)×t
t = [tex]\frac{-10 m/s}{-2 m/s^{2}}[/tex]
t = 5s
Answer:
t = 5 sec
Step-by-step explanation:
F = -20N
M = 10 kg
u = 10 m/s
v = 0 m/s
t =?
F = m × a
-20 = 10 × a
a = -2m/s²
v = u + at
0 = 10 + (-2) × t
-10÷(-2) = t
t = 5 sec