If a body of mass 2 kg changes its momentum from 25 kgm/s to 18 kgm/s in 0.14 s.
Then calculate the force acting on the body.
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If a body of mass 2 kg changes its momentum from 25 kgm/s to 18 kgm/s in 0.14 s.
Then calculate the force acting on the body.
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Given:-
→ Mass of the body = 2kg
→ Initial momentum = 25 kgm/s
→ Final momentum = 18 kgm/s
→ Time taken = 0.14 s
To find:-
→ Force acting on the body.
Solution:-
[Note : In this problem, we have no use of mass of the body.]
By Newton's 2nd law of motion, we know that :-
=> F = Δp/t
=> F = m(v - u)/t
∴ F = mv-mu/t
Where :-
• F is the force acting .
• mv is final momentum of the body.
• mu is initial momentum of the body.
• t is time taken.
By substituting values, we get :-
=> F = 18 - 25/0.14
=> F = -7/0.14
=> F = -700/14
=> F = -50 N
[Here, -ve sign represents retarding force]
Thus, force acting on the body is -50 N or a retarding force of 50 N .
Some Extra Information:-
2nd law of motion: The rate of change of momentum is directly proportional to the force applied and it will take place in the direction of force.
i.e. F ∝ Δp/t