A car accelerates from 6/s to 16 m/s in 10 sec calculate (a) the acceleration (b) the distance covered by car that time
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A car accelerates from 6/s to 16 m/s in 10 sec calculate (a) the acceleration (b) the distance covered by car that time
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Answer:
Initial velocity = u
u=6m/s
Final velocity = v
v=16m/s
Time=t=10s
⋅Acceleration=a
a=(v−u)/t
=(16−6)/10
=1m/s
2
⋅Distance=s
From the newton's second law,
s=
2a
(v
2
−u
2
)
s=
(2×1)
(256−36)
=110m