an object of mass 10kg moves at a constant speed of 10m/s.a constant force,that acts for 4s on the object gives it a speed 2m/s in opposite direction.the force acting on the object is
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an object of mass 10kg moves at a constant speed of 10m/s.a constant force,that acts for 4s on the object gives it a speed 2m/s in opposite direction.the force acting on the object is
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Answer:
F=m(v−u)t=10(−2−10)4=−30 N.
Answer:
The force acting on the object is 30 Newtons in the opposite direction.
EXPLANATION:
To find the force acting on the object, we can use Newton's second law of motion, which states that force is equal to the rate of change of momentum.
The momentum of an object is given by the product of its mass and velocity.
Initially, the object has a mass of 10kg and a velocity of 10m/s. So, its initial momentum is 10kg * 10m/s = 100 kg*m/s.
After the force acts on the object for 4 seconds, its final velocity becomes -2m/s (opposite direction).
The change in velocity is final velocity minus initial velocity, which is -2m/s - 10m/s = -12m/s.
The change in momentum is mass times the change in velocity, which is 10kg * (-12m/s) = -120 kg*m/s.
Since the time of application of the force is 4 seconds, we can calculate the force using the formula:
Force = Change in momentum / Time
Force = (-120 kg*m/s) / 4s = -30 N
Therefore, the force acting on the object is -30 Newtons, in the opposite direction.