Find the length of the conductor which is moving with a speed of 10 m/s in the direction perpendicular to the direction of magnetic field of induction 0.8T, if it induces an emf of 8V between the ends of the conductor.
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Answer:answer is 1 m
Induced EMF =Blvd sin theta
Explanation:
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[tex] \huge{ \underline{ \underline \mathfrak \purple{Required \: Answer}}}[/tex]
Given:-
To Find:-
Solution:-
By using the formula for e.m.f and substitution the value in it, we get :
[tex] \implies \: ε = Blv[/tex]
[tex]→8 = 0.8 \times 1 \times 10[/tex]
[tex]→ \frac{8}{10} \times 1 \times 10[/tex]
[tex]→8 = 8 \times 1[/tex]
[tex]→ \frac{8}{8} = 1[/tex]
[tex]→1 = I[/tex]
Therefore,