6.
The brakes applied to a car produces an acceleration of 6 m/s in the opposite direction to th
motion. If the car takes two seconds to stop after the application of brakes, calculate the distanc
it travels during this time.
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6.
The brakes applied to a car produces an acceleration of 6 m/s in the opposite direction to th
motion. If the car takes two seconds to stop after the application of brakes, calculate the distanc
it travels during this time.
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Answer:
Given:
Accerleration: a=−6 m/s
Time t=2 s
Final velocity, v=0 m/s
v=u+at
0=u−6×2
u=12 m/s
s=ut+1/2at^2
s= 12×2+1/2×(-6)×2^2
s = 24+(-6)×2×2/2
s= 24+(-6)×2
s= 24-12
s=12m
distance travelled by car is 12m
s = 12m