consider a particl moving along x axis with velocity v= 3tsquare+2t+1 m/s. its acceleration in t=2sec is?
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consider a particl moving along x axis with velocity v= 3tsquare+2t+1 m/s. its acceleration in t=2sec is?
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Answer:
At t=0, the particle is at a position 5 m, and at t=4 s the particle is at position 1 m.
Thus displacement of particle S=1−5=−4 m
Time taken t=4 s
Average velocity V
avg
=
t
S
=
4
−4
=−1 m/s
Slope of displacement-time graph gives the velocity of particle at that instant.
Slope of the graph is zero at t=4 s, thus velocity is zero at t=4 s.
it is based on velocity..stay safe