A train moving with a speed of 5 m/s obtains to an acceleration of 0.2 metre per second square. Calculate the speed of the train after 10 seconds, and the distance travelled by it in this time.
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s obtains to an acceleration of 0.2 metre per second square. Calculate the speed of the train after 10 seconds, and the distance travelled
Answer:
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Explanation:
u = 5 m/sec
a = 0.2 m/sec ^ 2
t = 10 sec
USING 1ST EQ OF MOTION,
v = u + at
v = 5 + 0.2×10
v = 5 + 2
v = 7 m/sec
FINAL VELOCITY = 7 m/sec
2nd EQ OF MOTION,
s = ut + 1/2 at^2
s = 5 × 10 + 1/2 × 2/10×10×10
s = 50 + 10
s = 60m
DISTANCE = 60 m
Verified answer
Explanation: A=V-U/T
=0.2=V-5/10
0.2*10=2
2=V-5
V=2+5=7=FINAL VELOCITY
By using 2nd equation:UT+1/2 AT^2
5*10+1/2 0.2*10^2
50+1/2 0.2*100=50+1/2*20
50+10=60 METERS