A bullet initially moving with a velocity 20 m/s strikes a target and comes to rest after penetrating a distance 10 cm in the target. Calculate the retardation caused by the target.
A bullet initially moving with a velocity 20 m/s strikes a target and comes to rest after penetrating a distance 10 cm in the target. Calculate the retardation caused by the target.
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Answer:
2000 m / sec²
Explanation:
Given :
Initial velocity u = 20 m / sec
When bullet comes to rest final velocity become zero i.e. v= 0
Distance s = 10 cm or 0.1 m
We have :
v² = u² + 2 a s
0² = 20² + 2 × a × 0.1
0 = 400 + ( 2 × a × 0.1 )
0 = 200 + 0.1 a
0.1 a = - 200
a = - 2000 m / sec².
Hence retardation caused by the target is 2000 m / sec².
Answer:
Given, v= 0
u= 20
S= 10= 0.1
We know that v^2= u^2 + 2aS =
0= 400 +2 x a x 0.1
0.2a= -400
a= -400/0.2
a= -2000
Therefore retardation= 2000 m/s^2