plz help........
A mass of 2.9kg suspended from a string of length 50cm is at rest . Another body of 100g moving horizontally with velocity 150m/s strikes and sticks to it. what is tension in the string when it makes the angle of 60degree with the horizontal?????
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ANSWER
Since the collision is perfectly inelastic, conserving momentum, we get,
0.1×150=(2.9+0.1)×u
u=5 m/s
After this, applying conservation of energy,
(m+M) g(l(1−cos(60))+ ½ (m+M)v²
= ½ (m+M)u²
½ (m+M)v² = ½(m+M)u² −(m+M)gl(1−cos(60)
(m+M)v² =3×5²−2×3×10×0.5×(1−0.5)
⟹(m+M)v² =60
T =(m+M)gcos(θ)+(m+M)v² /l
=15+120
T=135 N
i hope it helps you.