a block of metal weighing 2 kg is resting on a frictionless plane. it is strunk by a jet releasing Water at rate of 1 kg/s and at speed of 5 m/s the initial acceleration of block will
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a block of metal weighing 2 kg is resting on a frictionless plane. it is strunk by a jet releasing Water at rate of 1 kg/s and at speed of 5 m/s the initial acceleration of block will
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ANSWER
The final velocity of mass of water after hitting the metal block is zero.
So the average change in momentum per sec = initial momentum
=mass×initial velocity of water
=1kg×5m/s=5kgm/s
As this change in momentum occurs during 1 sec. We may say that the force exerted on the 2kg metal block is
F=change in momentumtime
=5kgm/s1s=5N
Hence by Newton's law initial acceleration of the block of mass m=2kg is given by
a=Fm=5N2kg=2.5m/s2
F = v dm/dt
= 5 x 1
= 5N
acceleration= a = F/m
= 5/2
= 2.5 ms⁻²