An object is moving with initial velocity 10 m/s with a constant acceleration of -2 m/s². The total distance travelled by the object in 6 sec
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An object is moving with initial velocity 10 m/s with a constant acceleration of -2 m/s². The total distance travelled by the object in 6 sec
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Answer:
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Explanation:
we know, equation for distance S travelled by obj. moving with acceleration a is given by,
S = ut+ 1/2 at^2
Here, u= 10m/s , a=-2 m/s^2, t=6s
therefore, S = 10×6 + 1/2× (-2) ×6^2
=60-36
= 24m