A car moves with an initial velocity 30m/s then stops after 10 sec. Find the retardation *
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A car moves with an initial velocity 30m/s then stops after 10 sec. Find the retardation *
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Given :
To find :
According to the question,
By using Newtons first equation of motion,
➞ v = u + at
Where,
➞ 0 = 30 + a × 10
➞ 0 - 30 = 10a
➞ - 30 = 10a
➞ - 30 ÷ 10 = a
➞ - 3 = a
So, the retardation of the car is 3 m/s²
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More formulas :
Newton's first equation of motion :
Newton's second equation of motion :
Newton's third equation of motion :
Answer:
Provided information :-
What to do :-
Find the retardation (A)
Let's solve :-
Here, we will use newton first Equation
➸ V = U + AT
[tex] \\ [/tex]
➸ 0 = 30 + a × 10
➸ 0 - 30 + 10a
➸ -30 = 10a
➸ -30 ÷ 10 = a
➸ -3 = a
✭ Retardation = 3 m/s ✭