a particle is thrown vertically upwards. its velocity at half the max height attained is 10m/s, then the max height attained by it is
a particle is thrown vertically upwards. its velocity at half the max height attained is 10m/s, then the max height attained by it is
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Hi mate
Question:
A particle is thrown vertically upwards. its velocity at half the max height attained is 10m/s, then the max height attained by it is
Solution
v² = u² − 2gh
For maximum height v=0 and h = H
so 2gH = u²
again at half of the height
(10)² = u² −2g(H/2) ⇒ 100 = 2gH − gH
∴gH = 100 ⇒ H= 100/10
=10m
∴ 10m is your answer
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