the particle is thrown up vertically with a velocity of 50m/s what will be iys velocity at the highest point of the journey how high would the particle rise what time would it take to reach the highest point.
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the particle is thrown up vertically with a velocity of 50m/s what will be iys velocity at the highest point of the journey how high would the particle rise what time would it take to reach the highest point.
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At the highest point it's velocity will be 0.
To find time:
v=u+at
0=50+(-10)t
10t=50
t=5 sec.
To find height:
S=ut+0.5at^2
S=250+(-5)25
S=250-125
S=125m
Hope it helped u!!!