A man weighing 80 kg is standing in a trolley weighing 320 kg. The normal contact force between man and trolley is equal to 10n newtons. Find the value of n. (g = 10 m/s2)
Share
A man weighing 80 kg is standing in a trolley weighing 320 kg. The normal contact force between man and trolley is equal to 10n newtons. Find the value of n. (g = 10 m/s2)
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
So net displacement of man in 1s is, 4−0.8=3.2m
Explanation:
check the im
age below