A marble rolling on a smooth floor has an initial velocity of 0.4m/s. If the floor offers retardation of 0.02m/s^2, calculate the time it will take to come rest.
Share
A marble rolling on a smooth floor has an initial velocity of 0.4m/s. If the floor offers retardation of 0.02m/s^2, calculate the time it will take to come rest.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
The initial velocity of marble is 0.4m/s.
And the retardation is 0.2m/s²,or a=-0.2m/s²
Now by first equation of motion
v=u+at
where u is initial velocity,v is final velocity a is acceleration and t is time.
Putting the values in the equation,we get
0=0.4+(-0.2)t. (final velocity is 0 because body comes to rest.)
or,0.2t=0.4
or,t=0.4/0.2=2s
hope this help you do like this only
it's just for a help not the answer hope
an example will help you