A car starting from rest is accelerated uniformly at the rate of 2 m/s^2. Determine the velocity of the car when it covers a distance of 50 m.
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A car starting from rest is accelerated uniformly at the rate of 2 m/s^2. Determine the velocity of the car when it covers a distance of 50 m.
I will mark u brainliest .
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Provided that:
To calculate:
Solution:
Using concept:
Using formula:
Required solution:
→ v² - u² = 2as
→ v² - (0)² = 2(2)(50)
→ v² - (0)² = 2(100)
→ v² - 0 = 200
→ v² = 200
→ v = √200
→ v = 14.14 m/s
→ Final velocity = 14.14 m/s
Answer:
14.14 m/s^2
Explanation:
We have to solve this from 3rd Equation of Motion i.e.
We know that car started from rest so its initial velocity will be 0 m/s.
So,
So,
2×2×50 =
200 =
14.14 m/s
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